Aptitude Question:
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if a^x=b^y=c^z and b^2=ac then find x+z/xz=?
Answer:
a^x=b^y=c^z=k(say)
then,
a=k^(1/x),b=k^(1/y),c=k^(1/z);..........(1)
given b^2=ac
{K^(1/y)}^2=k^(1/x)*k^(1/z);
k^(2/y)=k^(1/x+1/z)
2/y=1/x+1/z
2/y=x+z/xz
hence the answer is 2/y "100% it is correct answer"
then,
a=k^(1/x),b=k^(1/y),c=k^(1/z);..........(1)
given b^2=ac
{K^(1/y)}^2=k^(1/x)*k^(1/z);
k^(2/y)=k^(1/x+1/z)
2/y=1/x+1/z
2/y=x+z/xz
hence the answer is 2/y "100% it is correct answer"
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