Aptitude Question:
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Find the minimum value of 3x+4y if x^2y^3=12?
Answer:
by substitution , consider x=2/3 & y=3
satisfyng ,x^2y^3=12;(2/3)^2*3^3=12
so 3x+4y=14
satisfyng ,x^2y^3=12;(2/3)^2*3^3=12
so 3x+4y=14
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