C++ Operator Overloading Question:
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Output of this program?

#include <iostream>
using namespace std;
class Integer
{
int i;
public:
Integer(int ii) : i(ii) {}
const Integer
operator+(const Integer& rv) const
{
cout << "operator+" << endl;
return Integer(i + rv.i);
}
Integer&
operator+=(const Integer& rv)
{
cout << "operator+=" << endl;
i += rv.i;
return *this;
}
};
int main()
{
int i = 1, j = 2, k = 3;
k += i + j;
Integer ii(1), jj(2), kk(3);
kk += ii + jj;
}
a) operator+
operator+=
b) operator+=
operator+
c) operator+
operator+
d) None of the mentioned

C++ Operator Overloading Interview Question

Answer:

a) operator+
operator+=

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Output of Program?

#include <iostream>
using namespace std;
class sample
{
public:
int x, y;
sample() {};
sample(int, int);
sample operator + (sample);
};
sample::sample (int a, int b)
{
x = a;
y = b;
}
sample sample::operator+ (sample param)
{
sample temp;
temp.x = x + param.x;
temp.y = y + param.y;
return (temp);
}
int main ()
{
sample a (4,1);
sample b (3,2);
sample c;
c = a + b;
cout << c.x << "," << c.y;
return 0;
}
a) 5, 5
b) 7, 3
c) 3, 7
d) None of the mentioned

Output of this program?

#include <iostream>
using namespace std;
class myclass
{
public:
int i;
myclass *operator->()
{return this;}
};
int main()
{
myclass ob;
ob->i = 10;
cout << ob.i << " " << ob->i;
return 0;
}
a) 10 10
b) 11 11
c) error
d) runtime error