Hardest VxWorks Interview Preparation Guide
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VxWorks frequently Asked Questions by expert members with experience in VxWorks. These interview questions and answers on VxWorks will help you strengthen your technical skills, prepare for the interviews and quickly revise the concepts. So get preparation for the VxWorks job interview

8 VxWorks Questions and Answers:

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Hardest  VxWorks Job Interview Questions and Answers
Hardest VxWorks Job Interview Questions and Answers

1 :: What is priority inversion?

Priority inversion is a situation where in lower priority
tasks will run blocking higher priority tasks waiting for
resource (mutex). For ex: consider 3 tasks. A, B and C, A
being highest priority task and C is lowest. Look at
sequence of context swaps

A goes for I/O . unlocks mutex.
C was ready to run. So C starts running. locks mutex
B is ready to run. Swaps out C and takes mutex.
A is ready to run. but A is blocked as mutex is locked by B.
but B will never relinqishes the mutex as its higher
priority than C.

The solution to priority inversion is Priority inheritance.

2 :: What are the various methods to overcome it?

Priority Inheritance is the solution for priority
inversion. whenever a high priority task request for some
resource which is locked by a low priority task, the
priority of lower task is inherited to the priority of the
higher task. The instance it unlocks the resource the
prioity is changed to its original value.
Another solution for this is priority ceiling where you
inherit the priority of the lower task whenever a higher
task is created.Even if the higher priority task doesnot
request for the resource

3 :: What is another for creating a task without using taskspawn?

Instead of taskspawn
taskInit and taskActivate can be used to create task.
taskInit->It will initialize the task at specified address
taskActivate->It will activate the initialised task

4 :: Which RTOS supports Non-Preemptive scheduling? Why other scheduling methods are supported by such Oses?

The standard UNIX kernel is a nonpreemptive kernel; it does
not allow a user process to preempt a process executing in
kernel mode. Once a running process issues a system call and
enters kernel mode, preemptive context switches are disabled
until the system call is completed. Although there are
context switches, a system call may take an arbitrarily long
time to execute without voluntarily giving up the processor.
During that time, the process that made the system call may
delay the execution of a higher-priority, runnable, realtime

The maximum process preemption latency for a nonpreemptive
kernel is the maximum amount of time it can take for the
running, kernel-mode process to switch out of kernel mode
back into user mode and then be preempted by a
higher-priority process. Under these conditions it is not
unusual for worst-case preemption to take seconds, which is
clearly unacceptable for many realtime applications.

5 :: What do you mean by Semaphore and when we will go for using this?

semaphore is used to avoid the effect of dead lock.
there are three types of semaphore .
1)binary semaphore->it is only to acquire and release the
semaphore.zero is used for unavailabel and
one is used for available.
2)counting semaphore->when semaphore is acquired counter is
incremented and when semaphore is released conter is
decremented.when counter is zero it is goes to blocked state.
3)mutual exclusion->it is same as binary semaphore.but it is
used for safty purpose.it is two state locked state and
unlocked state.when semaphore is acquired it is goes to
locked state and when semaphore is released it goes to
unlocked state.

6 :: Suppose there is a global variable & a static global
variable.Both gets memory allocated from the data segment.
Then how does the visiblity of static global varible gets limited to the file alone
(in which it gets declared)

Static variables are local in scope to their module in which
they are defined, but life is throughout the program. Say
for a static variable inside a function cannot be called
from outside the function (because it's not in scope) but is
alive and exists in memory. The next time this function is
entered (within the same program) the same chunk of memory
would be accessed now retaining the variables old value and
no new memory is allocated this time for this variable like
other variables in the function (automatic variables). So
basically the variable persists throughout the program.
Similarly if a static variable is defined in a global space
(say at beginning of file) then this variable will be
accessible only in this file (file scope).

7 :: Write a code to connect Hardware interrupt to ISR and explain?

In Keil
void serial_ISR() interrupt 4 using 0

& in AVR studio

hardware intterupt normally redirects the uC to predefined
addresses. In case of high end processors the interrupt
table will decide the interrupt vector address and whenever
intterrupt pin goes low, the table is searched for type and
source of interrupt.

8 :: Explain task spawn in vxworks?

The VxWorks multitasking kernel, wind, uses interrupt-driven, priority-based task scheduling. It features fast context switch times and low interrupt latency. Under VxWorks, any subroutine can be spawned as a separate task, with its own context and stack. Other basic task control facilities allow tasks to be suspended, resumed, deleted, delayed, and moved in priority.
VxWorks Interview Questions and Answers
8 VxWorks Interview Questions and Answers