Linux Startup and Shutdown Question:
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What is the output of this program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
int *ptr1, *ptr2;
ptr1 = malloc(4);
*ptr1 = 10;
*ptr2 = free(ptr1);
printf("%dn",*ptr2);
return 0;
}
a) 10
b) it will print the address stored in ptr1
c) it will print the address stored in ptr2
d) it will give an error

Answer:

d) it will give an error
Explanation:
The free() function returns no value.
Output:
[root@localhost google]# gcc -o san san.c
san.c: In function 'main':
san.c:8:8: error: void value not ignored as it ought to be
[root@localhost google]#

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What is the output of this program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
int *ptr1;
while(1){
ptr1 = malloc(1024*1024);
if(ptr1 == 0)
break;
sleep(1);
printf("googlen");
free(ptr1);
}
return 0;
}
a) it will print "google" until the process has been stopeed by any signal
b) it will print nothing
c) segmentation fault
d) none of the mentioned		Do you have any idea what is the output of this program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
int *ptr;
*ptr = 10;
*ptr = 20;
printf("%dn",*ptr);
return 0;
}
a) 10
b) 20
c) segmentation fault
d) none of the mentioned