Linux Startup and Shutdown Question:
Download Questions PDF

Do you have any idea what is the output of this program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
int *ptr;
*ptr = 10;
*ptr = 20;
printf("%dn",*ptr);
return 0;
}
a) 10
b) 20
c) segmentation fault
d) none of the mentioned

Answer:

c) segmentation fault
Explanation:
The segmentation fault occurs because memory for the pointer has not been allocated in this program.
Output:
[root@localhost google]# gcc -o san san.c
[root@localhost google]# ./san
Segmentation fault (core dumped)
[root@localhost google]#

Download Linux Shutdown & Startup Interview Questions And Answers PDF

Previous QuestionNext Question
What is the output of this program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
int *ptr1, *ptr2;
ptr1 = malloc(4);
*ptr1 = 10;
*ptr2 = free(ptr1);
printf("%dn",*ptr2);
return 0;
}
a) 10
b) it will print the address stored in ptr1
c) it will print the address stored in ptr2
d) it will give an error		What is the output of this program?

#include<stdio.h>

int main()
{
int *ptr;
ptr = (int *)calloc(1,sizeof(int));
*ptr = 10;
printf("%dn",*ptr);
return 0;
}
a) 0
b) -1
c) 10
d) none of the mentioned