Firebird Question:
Download Job Interview Questions and Answers PDF
How to select a random record from a table?
Answer:
There is no such feature in Firebird, but you can use some tricks. The following example requires that you have a unique integer column (primary key is usually used):
SELECT ...field_list...
FROM table t1
WHERE conditions
ORDER BY (t1.int_col + seed)*4294967291-((t1.int_col + seed)*4294967291/49157)*49157;
If you just need one random record, limit the result set using FIRST or ROWS clause. This query will give consistent records for the same seed. If you wish to be completely random, you need to change the seed. You could use the value of int_col from previous run, or simply fetch a new value from a generator (just make sure the same value for seed is used in both places in expression).
SELECT ...field_list...
FROM table t1
WHERE conditions
ORDER BY (t1.int_col + seed)*4294967291-((t1.int_col + seed)*4294967291/49157)*49157;
If you just need one random record, limit the result set using FIRST or ROWS clause. This query will give consistent records for the same seed. If you wish to be completely random, you need to change the seed. You could use the value of int_col from previous run, or simply fetch a new value from a generator (just make sure the same value for seed is used in both places in expression).
Download Firebird Interview Questions And Answers
PDF
Previous Question | Next Question |
How to repair a corrupt Firebird database? | How to specify transaction or query timeout? |