Puzzles Interview Questions And Answers

The value of L must be one more than W i.e. L=W+1 and there must be one carry from S+I=I. Also, the value of S must be 9 as S+I=I with one carry from T+T=M, which means that the value of T must be greater than 4.
From I+H=I, the value of H must be 0 as the value of S is 9.

Now, applying all those constraints and using trial-n-error, we get two possible answers.

9 7 1 6 6 9 8 5 3 3

+ 5 1 7 0 1 3 + 2 5 8 0 5 6
--------------- ---------------
6 1 4 1 7 9 3 5 6 5 8 9

The second answer
258056
+98533
---------
356589

is wrong as the value of both N and M is 6 here.

I have tried all the combinations and there seems to be only one solution i.e. the first one
517013
+ 97166
----------
614179



The other constraints that i have found while solving the question are :

L cant be 1
N cant be 8
H = 0
T can have only values 6/7/8
and corresponding M is 2/4/6

Players from left to right : Bhavik, (Bhadrik/Bhanu), (Bhola/Bhumit), Bhagat, (Bhola/Bhumit), BHUVAN, Bhairav, (Bharat/Bhavesh), (Bharat/Bhavesh), (Bhadrik/Bhanu), Bhavin

Let's number the positions 1 to 11 from left to right. Hence, the captain is at position 6. Now, looking at the clues 7, 5, 2 and 8 together:

Poistion 1 - Bhavik or Bhairav
Position 3 - Bhumit or Bhola
Position 4 - Bhagat
Position 5 - Bhumit or Bhola
Poistion 7 - Bhavik or Bhairav
Position 11 - Bhavin

From clue (3), the only possible positions for Bhadrik and Bhanu are Position 2 and Position 10.

Now there are 3 positions remaining - 6, 8 and 9 and remaining 3 players are Bhuvan, Bharat and Bhavesh. But from clue (1), Bharat stood to the right of the captain i.e. Bharat must be on position 8 or 9 as position 6 is for the captain. So either Bhuvan or Bhavesh is the captain.

From (4), Bhavesh stood to the right of Bhuvan. Hence, Bhuvan is the captain.
Players from left to right are : Bhavik, (Bhadrik/Bhanu), (Bhola/Bhumit), Bhagat, (Bhola/Bhumit), BHUVAN, Bhairav, (Bharat/Bhavesh), (Bharat/Bhavesh), (Bhadrik/Bhanu), Bhavin.

Thus,
* Bhavik(1), Bhagat(4), Bhuvan(6), Bhairav(7) and Bhavin(11) are the players whose positions are fixed.
* Bhadrik and Bhanu are at position 2 or 10.
* Bhola and Bhumit are at position 3 or 5.
* Bharat and Bhavesh are at position 8 or 9.

3 square marks initially at location (1,1), (1,2) and (2,1). Then it marks all square by considering atleast 2 marks square.

For an nxn grid of square, initially n squares should be marked in appropriate places so as to obtain solution....

Appropriate places should be chosen such that 2 initially marked squares should be neighbor of an unmarked square... Other initially marked squares should be placed such that, it should help in marking further squares...

7.5 degrees

At 3:15 minute hand will be perfactly horizontal pointing towards 3. Whereas hour hand will be towards 4. Also, hour hand must have covered 1/4 of angle between 3 and 4.

The angle between two adjacent digits is 360/12 = 30 degrees.

Hence 1/4 of it is 7.5 degrees.

in a one minute minute hand travel six degree and in a one minute hour hand travel half degree.in a three o clock there is nienty degree angle so when minute hand travel ninty degree in 15 minute and hour hand also travel 7.5 degree.so there is 7.5 degree angle is formed.

We tried to find out some simple mathematical method and finally we wrote small C program to find out the answer. The answer is 3121 coins.

Here is the breakup:

First son = 624 coins
Second son = 499 coins
Third son = 399 coins
Forth son = 319 coins
Fifth son = 255 coins
Daughters = 204 each

No one is taller, both are same as A and B are the same person.

As it is mentioned that 500 men are arranged in an array of 10 rows and 50 columns according to their heights. Let's assume that position numbers represent their heights. Hence, the shortest among the 50, 100, 150, ... 450, 500 is person with height 50 i.e. A. Similarly the tallest among 1, 2, 3, 4, 5, ..... 48, 48, 50 is person with height 50 i.e. B

Now, both A and B are the person with height 50. Hence both are same.

In that question you mention 500 mens know then how will you say a&b both are persons
please clarify my doubt

The next letters in the series are N, O, R, S, U, X.
The pattern is - letters whose English names (Phonetic Pronunciations) start with vowels.

As the train had traveled a little bit distance to reach the bridge. hence the fuel has been reduced a little. thus the paper weight gets equated..

Total 4 persons (including you) required.

It is given that each person can only carry enough rations for five days. And there are 4 persons. Hence, total of 20 days rations is available.

1. First Day : 4 days of rations are used up. One person goes back using one day of rations for the return trip. The rations remaining for the further trek is for 15 days.

2. Second Day : The remaining three people use up 3 days of rations. One person goes back using 2 days of rations for the return trip. The rations remaining for the further trek is for 10 days.

3. Third Day : The remaining two people use up 2 days of rations. One person goes back using 3 days of rations for the return trip. The rations remaining for the further trek is for 5 days.

4. Fourth Day : The remaining person uses up one day of rations. He stays overnight. The next day he returns to the coast using 4 days of rations.

Thus, total 4 persons, including you are required.

This is a series with odd positions containing position number whereas even positions containing square of the position.i.e. even position numbers are 4 16 36 64 100 and odd position numbers are 1 3 5 7 9

Hence, 6 does not fit in the series. It should be 5.

The numebr is 420.

If statement 6 is false, it creates a paradox. Hence, Statement 6 must be true.
Consider Statement 2:
* If it is true, it must be the first true statement. Otherwise, it creates a paradox.

* If it is false, it must be the second false statement. Otherwise, it creates a paradox.

In both the cases, Statement 1 is false.

As Statement 1 is false, Statement 9 and Statement 10 both are false i.e. there are three consecutive true statements.
1 2 3 4 5 6 7 8 9 10
False - - - - True - - False False

Let's assume that Statement 3 is false i.e. there are no three consecutive false statements. It means that Statement 2 and Statement 8 must be true, else there will be three consecutive false statements.

1 2 3 4 5 6 7 8 9 10
False True False - - True - True False False

Also, atleast two of Statements 4, 5 and 7 must be true as there are three consecutive true statements.

According to Statement 8, the number that is to be found is the percentage of true statements. Hence, number is either 50 or 60. Now if Statement 7 is true, then the number of each true statement divides the number, that is to be found. But 7 and 8 do not divide either 50 or 60. Hence, Statement 7 is false which means that Statement 4 and 5 are true. But Statement 5 contradicts the Statement 8. Hence, our assumption that Statement 3 is false is wrong and Statement 3 is true i.e. there are 3 consecutive false statements which means that Statement 8 is false as there is no other possibilities of 3 consecutive false statements.

Also, Statement 7 is true as Statement 6 is not the last true statement.

1 2 3 4 5 6 7 8 9 10
False - True - - True True False False False

According to Statement 7, the number of each true statement divides the number, that is to be found. And according to Statement 5, the sum of the numbers of the true statements is the number, that is to be found. For all possible combinations Statement 5 is false.

There 3 consecutive true statements. Hence, Statement 2 and Statement 4 are true.

1 2 3 4 5 6 7 8 9 10
False True True True False True True False False False

Now, the conditions for the number to be found are:

1. The numebr is divisible by 5 (Statement 4)
2. The numebr is divisible by 2, 3, 4, 6, 7 (Statement 7)
3. The number of divisors of the number, that is to be found, (apart from 1 and itself) is not greater than the sum of the numbers of the true statements. (Statement 9)

The minimum possible number is 420.

The divisors of 420, apart from 1 and itself are 2, 3, 4, 5, 6, 7, 10, 12, 14, 15, 20, 21, 28, 30, 35, 42, 60, 70, 84, 105, 140, 210. There are total of 22 divisors. Also, the sum of the numbers of the true statements is 22 (2+3+4+6+7=22), which satisfies the third condition.

C=0, U=1, S=2, T=3, O=4, M=5, I=6, Z=7, E=8, D=9

It is obvious that U=1 (as U*STEM=STEM) and C=0 (as I-C=I).
S*O is a single digit and also S*T is a single digit. Hence, their values (O, S, T) must be 2, 3 or 4 (as they can not be 0 or 1 or greater than 4).

Consider, STEM*O=DMOC, where C=0. It means that M must be 5. Now, its simple. O=4, S=2, T=3, E=8, Z=7, I=6 and D=9.

O U T 4 1 3
------------- -------------
S T E M | D E M I S E 2 3 8 5 | 9 8 5 6 2 8

| D M O C | 9 5 4 0
------------- -------------
T U I S 3 1 6 2

S T E M 2 3 8 5
---------- ----------
Z Z Z E 7 7 7 8

Z U M M 7 1 5 5
-------- --------
I S T 6 2 3

Also, when arranged from 0 to 9, it spells CUSTOMIZED.

The next three numbers in the series are 4, 3, 4.

The pattern is - the number of 1's in the binary expansion of the positive integers starting from 1.

Number Binary Equivalent # of 1's

1 1 1
2 10 1
3 11 2
4 100 1
5 101 2
6 110 2
7 111 3
8 1000 1
9 1001 2
10 1010 2
11 1011 3
12 1100 2
13 1101 3
14 1110 3
15 1111 4
16 10000 1
17 10001 2
18 10010 2
19 10011 3
20 10100 2
21 10101 3
22 10110 3
23 10111 4
24 11000 2
25 11001 3
26 11010 3
27 11011 4
28 11100 3
29 11101 4

The first five girls each took an apple. The sixth girl took the basket as well as the apple in it.

They were the same man. Grover Cleveland (1837 - 1908) served two terms as president of the United States, but the terms were not consecutive. He was president from 1885 to 1889 and from 1893 to 1897.

The two men were partners playing doubles.

The man did not pass a single pub because he went into every one!

Let's say that William's father was 60, his mother was 25, and his mother's father was 45. Because everyone has two grandfathers, it is quite possible for a maternal grandfather to be younger than one's father.

The plane was parked on the runway.

The man had neglected to buy a new battery for his hearing aid. The old battery failed just as he was coming in to land and he therefore did not hear his tutor's crucial instructions.

The brothers were siamese twins, joined at the side. They lived in Birmingham, Albama. Because they drove on the right hand side of the road the steering wheel was on the left hand side of the car. The brother who sat on the left always drove. When they were in London, England, the other drove because the steering wheel was on the right hand side of the car.

The deaf man says to the storekeeper, " I would like to buy a saw, please.

Although the guards were looking in opposite directions, they were not back to back. They were facing each other.

Ben was born in the year 2000 B.C. So in 1985 B.C. he was 15 and in 1980 B.C. he was 20.

The girl was listening to the radio in her father's car. He drove through a tunnel and reception was temporarily interrupted.