Logical Question:

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A snail is at the bottom of a 20 meters deep pit. Every day the snail climbs 5 meters upwards, but at night it slides 4 meters back downwards. How many days does it take before the snail reaches the top of the pit?

Answer:

On the first day, the snail reaches a height of 5 meters and slides down 4 meters at night, and thus ends at a height of 1 meter. On the second day, he reaches 6 m., but slides back to 2 m. On the third day, he reaches 7 m., and slides back to 3 m. ... On the fifteenth day, he reaches 19 m., and slides back to 15 m. On the sixteenth day, he reaches 20 m., so now he is at the top of the pit! Conclusion: The snail reaches the top of the pit on the 16th day!... .

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3 salesmen went into a hotel to rent a room. The manager stated that he had only 1 room left, but all 3 could use it for $30.00 for the night. The 3 salesmen gave him $10.00 each and went up to their room. Later, the manager decided that he had charged the salesmen too much so he called the bellhop over, gave him five one-dollar bills, n said Take this $5.00 up to the salesmen n tell them I had charged them too much for the room. On the way up, the bellhop knew that he could not divide the 5 one-dollar bills equally so he put two of the one-dollar bills in his pocket and returned one one-dollar bill to each of the salesmen. It means that each salesman paid $9.00 for the room. The bellhop kept $2.00 3 times 9 is 27 plus 2 is 29. What happened to the extra?

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