Linux Search Pattern Question:

Tell us what is the output of this program?

#include<stdio.h>
#include<stdlib.h>
#include<fcntl.h>

int main()
{
int fd, count;
char ch, buff;
buff = (char )malloc(sizeof(char)*10);
fd = open("san.c",O_RDONLY);
count = read(fd,buff,5);
printf("%dn",count);
return 0;
}
a) 5
b) 10
c) 0
d) -1

Answer:

a) 5
Explanation:
The "read" system call returns the number of bytes successfully read.
Output:
[root@localhost google]# gcc -o san san.c
[root@localhost google]# ./san
5
[root@localhost google]#

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Linux Search Pattern Question:

Tell us what is the output of this program? #include<stdio.h> #include<stdlib.h> #include<fcntl.h> int main() { int fd, count; char ch, *buff; buff = (char *)malloc(sizeof(char)*10); fd = open("san.c",O_RDONLY); count = read(fd,buff,5); printf("%dn",count); return 0; } a) 5 b) 10 c) 0 d) -1

Answer:

Tell us what is the output of this program?

#include<stdio.h>
#include<stdlib.h>
#include<fcntl.h>

int main()
{
int fd, count;
char ch, buff;
buff = (char )malloc(sizeof(char)*10);
fd = open("san.c",O_RDONLY);
count = read(fd,buff,5);
printf("%dn",count);
return 0;
}
a) 5
b) 10
c) 0
d) -1