SNMP Question:
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What is the broadcast address of the subnet
address172.16.8.159\25?(choose from following)
172.16.99.255
172.16.127.255
172.16.255.255
172.16.64.127
172.16.64.260
Answer:
172.16.8.159 \ 25
172 16 8 159
10101100.00010000.00001000.10011111
8 +8 +8 +1 =25
11111111.11111111.11111111.10000000
Zeros mean, that you can change address bit, so
159=10011111 and last combination of 0011111 is changeable,
so max number in you network usually is broadcast address.
so last byte is 1(unchangeable)1111111(max sequence of
changeable bits).
11111111(bin) means 255(dec)
Whole address 10101100.00010000.00001000.11111111 =
172.16.8.255
172 16 8 159
10101100.00010000.00001000.10011111
8 +8 +8 +1 =25
11111111.11111111.11111111.10000000
Zeros mean, that you can change address bit, so
159=10011111 and last combination of 0011111 is changeable,
so max number in you network usually is broadcast address.
so last byte is 1(unchangeable)1111111(max sequence of
changeable bits).
11111111(bin) means 255(dec)
Whole address 10101100.00010000.00001000.11111111 =
172.16.8.255
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