C++ Operator Overloading Question:

A template function overloads itself as needed. But we can explicitly overload it too. Overloading a function template means having different sets of function templates which differ in their parameter list. Consider following example:

#include <iostream>

template <class X> void func(X a)
{
// Function code;
cout <<”Inside f(X a) \n”;
}

template <class X, class Y> void func(X a, Y b) //overloading function template func()
{
// Function code;
cout <<”Inside f(X a, Y b) \n”;
}

int main()
{
func(10); // calls func(X a)
func(10, 20); // calls func(X a, Y b)
return 0;
}