TCP/IP Question:
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Explain How many hosts can be on each network? Consider a fixed subnet partition of a class B network number that will accommodate at least 76 networks.?
Answer:
2^6=64 and 2^7=128
as per question, we need to accommodate 76 networks through fixed subnetting(ie VLSM is not asked for); so we need to use /23 mask which gives 128 subnets
No. of hosts per subnet = (2^9)-2 = 510
Subnet Address = 172.16.0.0
Subnet mask = 255.255.254.0
Valid subnets = 256-254 = 0,2,4,6...254
Subnet Example: for Subnet 0.0
First Host = 0.1
Last Host = 1.254
Broadcast = 1.255
as per question, we need to accommodate 76 networks through fixed subnetting(ie VLSM is not asked for); so we need to use /23 mask which gives 128 subnets
No. of hosts per subnet = (2^9)-2 = 510
Subnet Address = 172.16.0.0
Subnet mask = 255.255.254.0
Valid subnets = 256-254 = 0,2,4,6...254
Subnet Example: for Subnet 0.0
First Host = 0.1
Last Host = 1.254
Broadcast = 1.255
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