Answer:
Why doesn't
long int n = 123456;
printf("%dn", n);
work?
Whenever you print long ints you must use the l (lower case letter ``ell'') modifier in the printf format (e.g. %ld). printf can't know the types of the arguments which you've passed to it, so you must let it know by using the correct format specifiers.
long int n = 123456;
printf("%dn", n);
work?
Whenever you print long ints you must use the l (lower case letter ``ell'') modifier in the printf format (e.g. %ld). printf can't know the types of the arguments which you've passed to it, so you must let it know by using the correct format specifiers.
Previous Question | Next Question |
Why doesnt the call scanf work? | What is wrong with this code? |