MCAT (Medical College Admission Test) Question: Download Medical College Admission Test (MCAT) PDF
What is the work done by the force F? (Note: sin 60o = 0.87; cos 60o = 0.50. Ignore friction and the weights of the pulleys.)
Answer:
1. 50 J
2. 100 J
3. 174 J
4. 200 J
Answer: D
Explanation: Work is the product of force and distance. The easiest way to calculate the work in this pulley problem is to multiply the net force on the weight mg by the distance it is raised: 4 kg x 10 m/s2 x 5 m = 200 J. Therefore, answer choice D is the best answer.
2. 100 J
3. 174 J
4. 200 J
Answer: D
Explanation: Work is the product of force and distance. The easiest way to calculate the work in this pulley problem is to multiply the net force on the weight mg by the distance it is raised: 4 kg x 10 m/s2 x 5 m = 200 J. Therefore, answer choice D is the best answer.