Telecommunications Question:
What is the maximal decimal number that can be accommodated in a byte?
a) 128
b) 256
c) 255
d) 512
Answers:
Answer #1ITS 256.
SINCE, 1 BYTE=8 BITS
THE LOGIC IS 2^8=256(2 TO THE POWER OF 8)
SINCE, 1 BYTE=8 BITS
THE LOGIC IS 2^8=256(2 TO THE POWER OF 8)
Answer #2255
Answer #3its 255
because it\\'s from 0 to 255 so its 256 numbers but the max is 255
because it\\'s from 0 to 255 so its 256 numbers but the max is 255
Answer #4its 2^8-1 = 255
in an 8-bit register 0 to 255 devimal numbers can be stored/written
in an 8-bit register 0 to 255 devimal numbers can be stored/written
Answer #5255. the maximal base two number is 1111 1111 which converts to 255 in decimal. 256 is wrong answer. However, you can represent a total of 256 unique numbers with 8bits i.e 0 through to 255.
Answer #6answer is 255 because a byte contains 8 bits and maximum value is all 1's i.e 2^7+2^6+.......+2^1+2^0=256+128+64+32+16+8+4+2+1.
Answer #7the answer256 is correct in english terms if the network started with the #1 but instead its european standard is used 0-255 which equals 256.the #256 wouldn't be accepted.Just remember to count starting with 0
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