C++ Virtual Functions Question:
Tell me can a pure virtual function have an implementation?
Answers:
Answer #1The quick answer to that question is yes! A pure virtual function can have an implementation in C++ - which is something that even many veteran C++ developers do not know. So, using the SomeClass class from our example above, we can have the following code:
class SomeClass {
public:
virtual void pure_virtual() = 0; // a pure virtual function
// note that there is no function body
};
/*This is an implementation of the pure_virtual function
which is declared as a pure virtual function.
This is perfectly legal:
*/
void SomeClass::pure_virtual() {
cout<<"This is a test"<<endl;
}< /endl;
class SomeClass {
public:
virtual void pure_virtual() = 0; // a pure virtual function
// note that there is no function body
};
/*This is an implementation of the pure_virtual function
which is declared as a pure virtual function.
This is perfectly legal:
*/
void SomeClass::pure_virtual() {
cout<<"This is a test"<<endl;
}< /endl;
Answer #2The previous answer is correct. Marked it no by mistake.
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