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Please tell me output of this program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
int ptr;
ptr = (int )calloc(1,sizeof(int));
if (ptr != 0)
printf("%dn",*ptr);
return 0;
}
a) 0
b) -1
c) garbage value
d) none of the mentioned

Answer:

a) 0
Explanation:
The memory allocated by calloc() contains 0 until process does not make any change to it.
Output:
[root@localhost google]# gcc -o san san.c
[root@localhost google]# ./san
0
[root@localhost google]

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In this program the allocated memory block can store <pre lang="c" line="1" cssfile="hk1_style"> #include<stdio.h> #include<stdlib.h> int main() { int *ptr; ptr = malloc(10); return 0; } a) int b) char c) float d) all of the mentioned	Program given below will allocate the memory of ___ bytes for pointer "ptr". #include<stdio.h> #include<stdlib.h> int main() { int ptr; ptr = (int)malloc(sizeof(int)4); ptr = realloc(ptr,sizeof(int)2); return 0; } a) 2 b) 4 c) 8 d) none of the mentioned

Linux Startup and Shutdown Question: Download Linux Shutdown & Startup PDF

Please tell me output of this program? #include<stdio.h> #include<stdlib.h> int main() { int *ptr; ptr = (int *)calloc(1,sizeof(int)); if (ptr != 0) printf("%dn",*ptr); return 0; } a) 0 b) -1 c) garbage value d) none of the mentioned

Answer:

Please tell me output of this program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
int ptr;
ptr = (int )calloc(1,sizeof(int));
if (ptr != 0)
printf("%dn",*ptr);
return 0;
}
a) 0
b) -1
c) garbage value
d) none of the mentioned