PSAT/NMSQT Question:

How many four digit numbers exist which can be formed by using the digits 2, 3, 5 and 7 once only such that they are divisible by 25?

1. 4! - 3!
2. 4
3. 8
4. 6

Ans :B

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What is the total number of different divisors including 1 and the number that can divide the number 6400?	A certain number when successfully divided by 8 and 11 leaves remainders of 3 and 7 respectively. What will be remainder when the number is divided by the product of 8 and 11, viz 88?