PSAT/NMSQT Question: Download PSAT PDF

Given A = 265 and B = (264+263+262+...+20)

1. B is 264 larger than A
2. A and B are equal
3. B is larger than A by 1
4. A is larger than B by 1

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A number when divided by a divisor leaves a remainder of 24. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?	The sum of third and ninth term of an A.P is 8. Find the sum of the first 11 terms of the progression.