Answer:
P(x)= p x q n-x n!/[(n-x)!x!]
where n = number of trials
x = number of successes among n trials
p = probability of success in any one trial
q = 1 -p
where n = number of trials
x = number of successes among n trials
p = probability of success in any one trial
q = 1 -p
| Previous Question | Next Question |
| Explain example of Central Limit Theorem? | Explain about binary search? |