Statics Measures Question:

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Examine the output on p. 268. How would these results be reported?

Statics Measures Interview Question
Statics Measures Interview Question

Answer:

1. The chi square value of 10.490 (DF=317) achieved an associated p value of <.001. There was a significant difference between the expected and the observed frequencies. We can conclude that there is a greater prevalence of right handedness in women with IBS.
2. The chi square value of 317 (DF=1) achieved an associated p value of <.001. There was a significant difference between the expected and the observed frequencies. We can conclude that there is a greater prevalence of left handedness in women with IBS.
3. The chi square value of 10.490 (DF=1) achieved an associated p value of .001. There was no significant difference between the expected and the observed frequencies. We can conclude that being left or right handed is unrelated to IBS in women.
4. The chi square value of 10.490 (DF=1) achieved an associated p value of <.001. There was a significant difference between the expected and the observed frequencies. We can conclude that there is a greater prevalence of left handedness in women with IBS.

Answer: The chi square value of 10.490 (DF=1) achieved an associated p value of <.001. There was a significant difference between the expected and the observed frequencies. We can conclude that there is a greater prevalence of left handedness in women with IBS.

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You are conducting a one variable chi square test to test the hypothesis that there are equal numbers of vegetarians, meat eaters, and vegans eating at the student union. The categories are vegetarian, meat eaters, and vegans. Having conducted a survey, you found 85 individuals were vegetarian, 122 ate meat, and 32 followed a vegan diet. What would the expected frequencies be in each cell?Although in one variable chi square testing each participant cannot be in more than one group, in a 2x2 chi square test, this rule does not apply?