Energy Engineering Question: Download Energy Engineering PDF
A 3.3 k resistor dissipates 0.25 W. The current is
A. 8.7 mA
B. 87 mA
C. 8.7 µA
D. 8.7 A
Answer:
Option A
Explanation:
W = I2R
I = square root(W/R)
= square root( 0.25/(3.3x1000) )
= 0.0087038828
= 8.7 mA
Explanation:
W = I2R
I = square root(W/R)
= square root( 0.25/(3.3x1000) )
= 0.0087038828
= 8.7 mA
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