Quantitative Aptitude Interview Preparation Guide
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Quantitative Aptitude frequently Asked Questions by expert members with experience in Quantitative Aptitude. So get preparation for the Quantitative Aptitude job interview

55 Quantitative Aptitude Questions and Answers:

2 :: In a group of 15, 7 have studied Latin, 8 have studied Greek, and 3 have not studied either. How many of these studied both Latin and Greek?
A. 0
B. 3
C. 4
D. 5

L=7
G=8
Total number of students(U)=15
Number of students who study neither of them (N)=3
draw a simple diagram representing the above situation.
we need to find out L INTERSECTION G.
Thus we have,
L UNION G + N = 15
L UNION G = L + G - L INTERSECTION G = 7 + 8 - L INTERSECTION G
L INTERSECTION G= 7 + 8 +N-15
= 7+8+3-15
= 3

3 :: Explain series: 2,7,24,77,.

Ans is:

2*3+1=7

7*3+3=24

24*3+5=77

77*3+7=238

Therefore ans is 238

4 :: What is the largest prime no. stored in 8bit/6bit/9bit/7bit memory?
A,B,C are the mechanisms used separately?

for 6 bit maximum allowed number is 64 prime number is 61

for 7 bit maximum allowed number is 128 prime number is 127

for 8 bit max allowed number is 256 prime number is 253

for 9 bit max allowed number is 512 prime number is 511

6 :: 1/3 of a number is 3 more than 1/6 of the same number.
What is the number?

let x be a no
now 1/3 of a no is x/3


and again

x/3=x/6+3
x/3-x/6=3.

x=18

8 :: How many 5 digit numbers can be formed using the digits 1, 2, 3, 4, 5 (but with repetition) that are divisible by 4?

Divisibility rule of 4 is last two digits are divisible by 4
so in 5 digit no last two digit should always be 12,24,32,44,52;
(any one of them may be)

so for last two digits 5 ways are possible ;

since repetion are allowed then for 3rs place form right there are also 5 ways so in 3rd place either of 1,2,3,4,5 is possible;
simillarly at 4 rth place either of 1,2,3,4,5 is possible so again 5 ways are possible

simillarly at 5th place also 5 ways are possible

so total no are: 5*5*5*5=625

9 :: If A is traveling at 72 km per hour on a highway. B is
traveling at a speed of 25 meters per second on a highway.
What is the difference in their speeds in m/sec?

ya the answer is 5sec..
converting 72kmph in m/sec we get 20m/sec
so 25-20=5sec/m

10 :: The cost of one pencil, two pens and four erasers is Rs.22 while the cost of five pencils, four pens and two erasers is Rs.32.How much will three pencils, three pens and three erasers cost?

Let a, b, and c denote pencil, pen and eraser respectively.

Given that the cost of one pencil, two pens and four erasers is Rs.22

This can be written as,

a + 2b + 4c = 22 ..........(1)

Similarly, the cost of 5 pencils, 4 pens and 2 erasers is Rs. 32

This implies ....

5a + 4B + 2c = 32 ......... (2)

Adding (1) and (2), we get

6a + 6b + 6c = 54

We need to find the value of 3a + 3b + 3c.

Dividing by 2, we get

3a + 3b + 3c = 27.

Hence, the cost of 3 pencils, 3 pens, and 3 erasers is Rs.27